Home

Line z intersecting pq at m drawing

Repeat step 1, but make the centre of your circle the other end point of the line segment (M). Step 3. Join the points where the circles intersect: PQ \(\perp \) MN. You are given line segment XY with point Z on it. You must construct a perpendicular line passing through Z. Step Draw line l with point M. Draw arc around M, radius is z. Construct line perpendicular to l and through M. Measure distance h on line from M (MP = h). Construct line m through P and parallel to l. intersection of m and circle is C. ABC is the triangle. LC holds is opposite diameter AB so LC = 90 degrees. z is radius of circle through A,B and C Find all the points of intersection of the line x = -1 + t; y = 5 + t; z = 8t + 28 and the surface z = x^2 + y^2. b. At each point of intersection, find the cosine of the acute angle between the.. Construct a line that will intersect Line $\overline{AB}$. Label the line and intersection point, then name four angles formed by the two intersecting lines. Solution. Construct a second line that intersects Line $\overline{AB}$. Below are three pairs of intersecting lines to guide you in creating your own pair of intersecting lines

Draw a rough figure and label suitably in each of the following cases: (a) Point P lies on line segment AB (b) XY and PQ Intersect at M. (c) Line l Contains E and F but not D. (d) OP and OQ meet at O. Solution: (a) AB is the line segment and point P lies on it pointsX, Y, and Z 9. Name the point at which line m intersects planeR. pointZ 10. Name two lines in plane R that intersect line m. ‹__› XZand ‹__› YZ 11. Name a line in plane R that does not intersect linem. ‹__› XY Draw your answers in the space provided. Michelle Kwan won a bronze medal in figure skating at the 2002 Salt Lake City. To find the intersection of two straight lines: First we need the equations of the two lines. If you do not have the equations, see Equation of a line - slope/intercept form and Equation of a line - point/slope form (If one of the lines is vertical, see the section below). Then, since at the point of intersection, the two equations will have the same values of x and y, we set the two equations.

Construction of geometric figures Construction of

  1. d Draw a line through A and B to cut PQ at M e Measure PM and MQ and PMA and. D draw a line through a and b to cut pq at m e. School Mufulira College of Education; Course Title COMPUTER 321; Uploaded By AmbassadorRiver4433. Pages 141 This preview shows page 89 - 95 out of 141 pages
  2. According to the property of corresponding angles ¨if two lines are parallel with a line intersecting them both, there corresponding angles formed by the intersecting line are equal.¨ This proves that angle 4 is equal to 8 because they are in the same place on the lines. Meaning on line PQ 4 is in the same place as 8 on line RS
  3. ed by a point (a;b;c) on the line and a direction ~v that is parallel(1) to the line. The set of points on this line is given by fhx;y;zi= ha;b;ci+ t~v;t 2Rg This represents that we start at the point (a;b;c) and add all scalar multiples of the vector ~v
  4. Step 4: Draw a line that passes through the two points of intersection, points P and Q. Line PQ is perpendicular to segment CD. In this construction, line PQ bisects segment CD. Therefore, PQ HJJG is a perpendicular bisector ofCD. C D P Q M PQ CD⊥ HJJ
  5. Introduction About the purposes of studying Descriptive Geometry: 1. Methods and means for solving 3D geometrical construction problems. In this sense Descriptive Geometry is a branch of Geometry. 2. 2D representation of 3D technical object, i.e. basics of Technical Drawing, instrument in technical communication
  6. With P and Q as centres, draw arcs on both sides of PQ with equal radii. The radius should be more than half the length of PQ. Let these arcs cut each other at points R and RS. Join RS which cuts PQ at D. Then RS = PQ Also POR = 90; Hence, the line segment RS is the perpendicular bisector of PQ as it bisects PQ at P and is also perpendicular to PQ
  7. Ex 4.1, 5 Draw a rough figure and label suitably in each of the following cases: (a) Point P lies on () ̅ . Point P lies on line segment () ̅ Ex 4.1, 5 Draw a rough figure and label suitably in each of the following cases: (b) () ⃡ and () ⃡ intersect at M. Lines () ⃡ and () ⃡ in

geometry construction answer

(i) Draw a line l and take a point P on line l. Then, draw a perpendicular at point P. (ii) Adjusting the compasses up to the length of 4 cm, draw an arc to intersect this perpendicular at point X. Choose any point Y on line l. Join X to Y. (iii) Taking Y as centre and with a convenient radius, draw an arc intersecting l at A and XY at B 5. Taking M as centre and any radius, draw an arc to intersect the line segments MN and ML at P and Q respectively. 6. Next, taking P and Q as centres and with the radius more than PQ, draw arcs to intersect each other, say at R. 7. Draw the ray MR. This ray MR is the required bisector of the ∠M Draw a diagonal scale to read single meter. Show a distance of 438 m on it. Draw a line 15 cm long. It will represent 600 m.Divide it in six equal parts. ( each will represent 100 m.) Divide first division in ten equal parts.Each will represent 10 m. Draw a line upward from left end and mark 10 parts on it of any distance

Intersection Euclidean Geometry Questions and Answers

Created with That Quiz — the site for test creation and grading in math and other subjects.That Quiz — the site for test creation and grading in math and other subjects Through X, draw a line m parallel to l. Let's first draw perpendicular to line l at point P 1. Given a line l with point P marked on it Let's first draw perpendicular to line l at point P 1. Given a line l with point P marked on it 2. With P as center, and any radius, draw an arc intersecting the line at points A and B 3 Draw a line parallel to AB through C. Draw a perpendicular from A and the point of intersection of perpen-dicular and parallel line is P. Then draw ∆ABP then ∠BAP = 90°. Areas of ∆ABC and ∆ABP are equal. 2. Draw a line parallel to BC through A from C make angle 60° both lines intersect at point Q. Then draw ∆ BCQ

Step 2. From each arc on the line, draw another arc on the opposite side of the line from the given point (P). The two new arcs will intersect. Step 3. Use your ruler to join the given point (P) to the point where the arcs intersect (Q). PQ is perpendicular to AB. We also write it like this: PQ ⊥ AB The intersection of EF, HI, and j.G is pðipt G, The intersection of plane EGH and plan€.JÇI is poiht G. F The intersection of plane EFI and plane JKG is I-IG. 10. 12. Sketch the figure described. 9. 11. Two rays that do not intersect Three lines that intersect in three points Thrèe planes that intersect in one line 11. On the diagram, draw planes M and N that intersect at line k. In Exercises 8—10, sketch the figure described. 12. plane A and line c intersecting at all points on line c 13. plane A and line intersecting at point C BC GM 14. line <--+ and plane X not intersecting CD 15.3 lines a, b, and c intersecting at three point Step4: With B,C as centers draw arcs of radius more than half the length of BC on both sides of BC. Let these arcs meet at P and Q . Step 5: Join PQ to meet BC at M. (Note that PQ bisects BC and is perpendicular to BC) Step6: With A,C as centers draw arcs of radius more than half the length of AC on both sides of AC. Let these arcs meet at T and U Given a line segment AB, we want to construct its perpendicular bisector . Steps of Construction : 1. Taking A and B as centres and radius more than 1 2 AB, draw arcs on both sides of the line segment AB (to intersect each other). 2. Let these arcs intersect each other at P and Q. Join PQ (see Fig.11.2). 3. Let PQ intersect AB at the point M.

Intersecting Lines - Story of Mathematic

With the help of a compass draw an arc at the center of the line say point O, such that it intersects the line at two points and at equidistant from O. Let the two points be P and Q. Again at point P and Q, draw the arc inside, such that the two arcs intersect each other at the top and bottom of the horizontal line any pair of points can be connected by a line segment that's right connect two pairs of black points in a way that creates two parallel line segments so let's see if we can do that so I could create one segment that connects these this point to this point and then another one that connects this point to this point and they look pretty parallel in fact I think this is the right answer if we did.

Draw a rough figure and label suitably in each of the

Use a ruler to draw a 15-cm line segment on a piece of tracing paper. Label the endpoints A and B. 2. Fold the piece of paper so that points A and B lie on top of each other. 3. Use a ruler to draw a line segment on the crease. Label this line segment CD. Label the point where the two line segments intersect P. 4. Use a ruler to measure lengths. Use your straight edge to draw a segment. Label one endpoint K and the other endpoint L.; Somewhere on your paper, away from K and L, draw a straight line m.We will call line m our working line. Now pick any point on line m.We will call this point K'. (We will use prime marks (') to make it easier to recognize which points correspond.)The point K' on line m will correspond with point K, the. Combined Equation of Pair of Lines joining Origin and Intersection Points of a Curve and a Line. Let us find the equation of the straight lines joining the origin and the points of intersection of the curve. a x 2 + 2 h x y + b y 2 + 2 g x + 2 f y + c = 0 ax^2+2hxy+by^2+2gx+2fy+c=0 a x 2 + 2 h x y + b y 2 + 2 g x + 2 f y + c = 0

Intersecting lines. (Coordinate Geometry) - Math Open ..

Draw an arc. It should intersect the other arc at two points. Bisect segment Draw a line through the two points of intersection. This line is the perpendicular bisector of AB —. It passes through M, the midpoint of AB —. So, AM = MB. P m The perpendicular bisector of a line segment PQ — is the line n with the following two properties Construction: Draw a line RU parallel to ST through point R. ∠RST + ∠SRU = 180° | Sum of the consecutive interior angles on the same side of the transversal is 180 Exercise 4.6. Question 6. Q5) Draw a rough figure and label suitably in each of the following cases: (a) Point P lies on . A B ‾ \overline {AB} A B. (b) X Y ‾ \overline {XY} X Y and P Q ‾ \overline {PQ} P Q intersect at M. (c) (c) Line l contains E and F but not D Steps of construction: (a) Draw a line l and take a point P on it. (b) At point P, draw a perpendicular line n. (c) Take PX = 4 cm on line n. (d) At point X, again draw a perpendicular line m. Given figure is the required construction. 3. Let l be a line and P be a point not on l

Subtracting these we get, (a 1 b 2 - a 2 b 1) x = c 1 b 2 - c 2 b 1. This gives us the value of x. Similarly, we can find the value of y. (x, y) gives us the point of intersection. Note: This gives the point of intersection of two lines, but if we are given line segments instead of lines, we have to also recheck that the point so computed actually lies on both the line segments (i) Draw a line segment and mark a point M on it. (ii) Taking M as centre and a convenient radius, construct an arc intersecting the line segment at points X and Y respectively. (iii) By taking centres as X and Y and radius greater than XM, construct two arcs such that they intersect each other at point D

Now we construct another line parallel to PQ passing through the origin. This line will have slope `B/A`, because it is perpendicular to DE. Let's call it line RS. We extend it to the origin `(0, 0)`. We will find the distance RS, which I hope you agree is equal to the distance PQ that we wanted at the start The two circles intersect at M and N, where N is closer to PQ than M is. Prove that the triangles MNP and MNQ have equal areas. Problem 20 [BMO] Two intersecting circles C 1 and C 2 have a common tangent which touches C 1 at P and C 2 at Q. The two circles intersect at M and N, where N is closer to PQ than M is. The line PN meets the circle We want to find a vector equation for the line segment between P and Q. Using P as our known point on the line, and − − ⇀ aPQ = x1 − x0, y1 − y0, z1 − z0 as the direction vector equation, Equation 12.5.4 gives. ⇀ r = ⇀ p + t(− − ⇀ aPQ). Equation 12.5.8 can be expanded using properties of vectors The intersection of plane ABC and line m is point P. c. Line ! and line m do not intersect. d. Points A, P,and B can be used to name plane U. e. Line ! lies in plane ACB. 3. Complete the figure at the right to show the following relationship: Lines !, m, and n are coplanar and lie in plane Q. Lines ! and m intersect at point P. Line

Geometry CC RHS Unit 1 Points, Planes, & Lines 7 16) Points P, K, N, and Q are coplanar. TRUE FALSE 17) If two planes intersect, then their intersection is a line. TRUE FALSE 18) PQ has no endpoints. TRUE FALSE 19) PQ has only TRUEone endpoint. FALSE 20) A line segment has exactly one midpoint. TRUE FALSE 21) Tell whether a point, a line, or a plane is illustrated by Given a line and a point, construct a line through the point, parallel to the gi ven line. 1. Begin with point P and line k. 2. Draw an arbitrary line through point P, intersecting line k. Call the intersection point Q. Now the task is to construct an angle with vertex P, congruent to the angle of intersection. 3. Center the compass at point The intersecting chords theorem or just the chord theorem is a statement in elementary geometry that describes a relation of the four line segments created by two intersecting chords within a circle. It states that the products of the lengths of the line segments on each chord are equal. It is Proposition 35 of Book 3 of Euclid's Elements.. More precisely, for two chords AC and BD intersecting.

Lines and Angles Class 9 Extra Questions Very Short Answer Type. Question 1. If an angle is half of its complementary angle, then find its degree measure. Solution: Let the required angle be x. ∴ Its complement = 90° - x. Now, according to given statement, we obtain. x = (90° - x) ⇒ 2x = 90° - x Po Draw a figure like the accompanying one, then describe how to construct line m through P parallel to L, using each of the following figures a. Perpendicular lines b. A quadrilateral whose diagonals bisect each other. (Hint: Connect with any point on L. Through the midpoint Mof PO draw any line intersecting Lato) a I see quite a few problems of this sort, so let's solve the general case first: Given circles centered on A and B, intersecting at C and D, and E being the intersection of AB and CD; and given values for AB and AC and CD; how do we solve for BC? E..

d Draw a line through A and B to cut PQ at M e Measure PM

Draw a line n which is parallel to line m at a distance of 4 cm from it. Answer: Steps of construction : (1) Draw a line m. (2) Take two points A and B on the line m. (3) Draw perpendiculars to the line m at A and B. (4) On the perpendicular lines, take points P and Q at a distance of 4 cm from A and B respectively Line. A geometrical object that is straight, infinitely long and infinitely thin. Try this Drag the orange dot at P or Q and see how the line PQ behaves. In the figure above, the line PQ passes through the points P and Q, and goes off in both directions forever, and is perfectly straight. A line, strictly speaking, has no ends (v) Join PQ which intersect AB at D. Then PD is perpendicular to AB. Properties of Angles and Lines Exercise 25D - Selina Concise Mathematics Class 6 ICSE Solutions. Question 1. Draw a line segment OA = 5 cm. Use set-square to construct angle AOB = 60°, such that OB = 3 cm. Join A and B ; then measure the length ofAB. Solution: Measuring the. Let R(x, y, z) divide PQ internally in the ratio m:n. Draw PL, QM, RN ⊥r ' to XY-plane. ∴ PL ∥ RN ∥ QM. ∴ PL, QM, RN lie in one plane so that the points L, N, M lie in a straight line which is the intersection of this plane and XY plane, through the point R draw a line AB parallel to the line LM

Draw a line segment AB = 6.8 cm. Take any point P outside it, using ruler and compass we can draw a line (b) intersecting with AB (d) none of these (a) parallel to AB (c) coincident with AB 9th Standard Maths Notes Kerala Syllabus Question 1. Draw a triangle of sides 3,4 and 6 centimeters. Draw three different right triangles of the same area. Draw a line parallel to AB through C and a line from B perpendicular to the parallel line, both lines intersect at point E. Now ∆ABE is a right angled triangle A line is a collection of points along a straight path with no end points. A line segment is a part of a line that contains every point on the line between its end points. PQ Plane EFG or Plane T. Points, Lines and Planes Point A point has zero dimensions. M Z N Collinear and non-collinear points Sheet 3. Printable Math Worksheets @ www. Draw a line of 6.5 centimetres long and draw its perpendicular bisector. Solution: Draw a line segment AB of length 6.5 c.m with A and B as centres draw arcs on both sides of AB with equal radii. The radius of each of these arcs must be more the half the length of AB. Let these arcs cut each other at points C and D. Join CD which cuts AB at M

Let two circles O and O' intersect at two points A and B so that AB is the common chord of two circles and OO' is the line segment joining the centres Let O O ′ intersect AB at M Now Draw line segments O A, O B, O ′ A a n d O ′ B In Δ O A O ′ a n d O B O ′, we have O A = O B (radii of same circle) O ′ A = O ′ B (radii of same. View Notes - L06-2017 from MAAE 2001 at Carleton University. MAAE 2001 Engineering Graphical Design Sections A and B Lecture 6 Points, Lines, Planes, and Descriptive Geometry (Chapters 7, 18 Proof: Radius is perpendicular to tangent line. Determining tangent lines: angles. Determining tangent lines: lengths. Proof: Segments tangent to circle from outside point are congruent. This is the currently selected item. Tangents of circles problem (example 1) Tangents of circles problem (example 2) Tangents of circles problem (example 3. A line passing through two points on a circle is called a secant. A line external to a circle, passing through one point on the circle, is a tangent. The Lesson: We show circle O below in figure a. Points A, B, C, and D are on the circle. The segments AP and DP are secants because they intersect the circle in two points The intersection of two lines can be generalized to involve additional lines. Existence of and expression for the n-line intersection problem are as follows.. In two dimensions. In two dimensions, more than two lines almost certainly do not intersect at a single point. To determine if they do and, if so, to find the intersection point, write the i-th equation (i = 1, ,n) as [] [] =, and.

The figure below shows a transversal t which intersects

Put the correct letter in the box. Obtuse Angle. Parallel lines. Point. Skew. Use lower case letters. b. An angle between. 90 and 180 degrees 8. End M of a line MN which is inclined at 46. o. to H.P. & 20. o. to V.P. is 15mm above the H.P. & it is in front of the V.P., while the end N is 60mm in front of V.P. & is above H.P. Draw the projections of the line, find its true length, if its plan length is 70mm. Locate the points of intersection of the line with the principal planes. 9 98 Chapter 2 Reasoning and Proof EXAMPLE 3 Use given information to sketch a diagram Sketch a diagram showing ‹]› TV intersecting}PQ at point W, so that}TW>}WV Solution STEP 1 Draw TV and label points T and V. STEP 2 Draw point W at the midpoint of}TV Mark the congruent segments. STEP 3 Draw}PQ through W. PERPENDICULAR FIGURES A line is a line perpendicular to a plane if and only if th For any two points P and Q, there is exactly one line PQ through the points. If the coordinates of P and Q are known, then the coefficients a, b, c of an equation for the line can be found by solving a system of linear equations. Example: For P = (1, 2), Q = (-2, 5), find the equation ax + by = c of line PQ 9. Name the point at which line m intersects plane .R _____ 10. Name two lines in plane R that intersect line m. _____ 11. Name a line in plane R that does not intersect line m. _____ Draw your answers in the space provided. Michelle Kwan won a bronze medal in figure skating at the 2002 Salt Lake City Winter Olympic Games. 12

Step 1: Draw a line segment A B ― and mark any point M on it. Step 2: Place pointer at A as center, and radius more than AM, draw an arc. With B as center, and same radius as before, draw an arc. Step 3: Mark the point of intersection of the two arcs as point N Join M & N. Ex 14.4 Class 6 Maths Question 2 In a plane, a line is tangent to a circle if and only if the line is perpendicular to a radius of the circle at its endpoint on the circle. Proof Ex. 47, p. 536 Theorem 10.2 External Tangent Congruence Theorem Tangent segments from a common external point are congruent. Proof Ex. 46, p. 536 Q P m P S T R S P T 35 37 12 B A 50 ft C 80 ft r r.

Lines PQ and XY do not meet at a right angle. So, the two lines are not perpendicular lines. Practice Unlimited Questions. 2. The following figure is a rectangle. QR is a straight line. Draw a line parallel to it. Count the number of unit squares between the two lines and make sure it is always the same Find an answer to your question draw the rough figure of following :- line segment PQ II .) LINE SEGMENT XY 2.) LINE M INTERSECTING LINE N AT POINT Academia.edu is a platform for academics to share research papers 9. Z 8 and Z 13 ll. z 5andZ7 F 13. z I and Z 2 15. ZIOand z 16 8. 10. 12. 16. Zl and Z 12 C. Z 2 and z 10 É Z 6 and Z 16 Z5and z 13 -E— Z13and z 15 9 10 12 11 13 14 16 15 Rd F. vertical G. linear pair Describe the relationship between the pairs of angles by circling the word that makes the sentence true. 17. If lines are parallel, the Draw intersecting arcs above and below BC. Label the points of intersection R and S. Use a straightedge to find the point where RS intersects BC. Label the midpoint M. Draw a line through A and M. AM is a median of ABC. A R C B S M 3 2 3 0 4 A R C B S M 2 A R C B S 1 Draw a triangle like ABC. Adjust the compass to an opening greater than AC 1 2.

Video: q4-draw-a-line-segment-pq-8cm- LID

Really just for fun. This code took less than 10 minutes to write and uses tools and a syntax that can be used everywhere, also in 3d drawings, in pgfplots and so on. I personally find the syntax also very intuitive to learn, and I am a big fan of pgf keys and the calc syntax. \documentclass [tikz,border=3mm] {standalone} \usetikzlibrary. The intersection of two planes is a line. The crease of a book The edge of a door A river valley The corner where two walls meet Check for Understanding Model Problems Draw and label each of the following. A. Plane H that contains two lines that intersect at M rays B. ⃡ intersecting plane M at R Drawing Hints Now, let us find out the relation between the angles in these pairs when line m is parallel to line n. You know that the ruled lines of your notebook are parallel to each other. So, with ruler and pencil, draw two parallel lines along any two of these lines and a transversal to intersect them as shown in Fig. 6.19 12.) A line and a plane that intersect at one point. 6 In Exercises 13-20, use the diagram. 13.) Name the intersection of KL and PQ. 14.) Name the intersection of PQ and plane KMN. 15.) Name the intersection of plane R and plane S. Critical Thinking (Draw the diagram.) In each diagram, M is the midpoint of the segment. Find the indicated. O Draw a semicircle on the line PQ, with O as centre and OA as radius to intersect PQ at AB. With A as centre and OA as radius, cut an arc on the semicircle.Similarly with B as centre and OA as radius, cut an arc on the semicircle.Now with these new points of intersections as centers, draw two arcs to intersect each other above O. Join this.

Draw an arc. It should intersect the other arc at two points. Bisect segment Draw a line through the two points of intersection. This line is the perpendicular bisector of —AB . It passes through M, the midpoint of AB —. So, AM = MB. P m The perpendicular bisector of a line segment PQ — is the line n with the following two properties Two planes either intersect at a common line or are parallel. When planes intersect, the problem of finding the intersection of two planes reduces to finding two lines in a plane and then the piercing points for each of these lines with respect to the other plane; the piercing points define the line where the planes intersect. 6-1 (a) Draw a line 70 mm long and trisect it. (b) Draw an angle of 65 0 with the help of a protector and trisect it. (c) Draw a line 60 mm long and divide it into 7 equal parts 21 To mark the end of a race, a finish-line banner is stretched across the road as shown in the drawing. Which is closest to the length of the support rope designated by xin the drawing? A 9.5 ft B 10.6 ft C 12.0 ft D 15.0 ft x 7 ft 8 ft Finish Line VASpr08 EOC Geom RB 3/28/08 8:36 AM Page 2 Click hereto get an answer to your question ️ In the Fig. lines PQ and RS intersect each other at point O. If POR : ROQ = 5 : 7 , Find all the angles

5.0000 5.0000 APL [] ⍝ APL has a powerful operator the « dyadic domino » to solve a system of N linear equations with N unknowns ⍝ We use it first to solve the a and b, defining the 2 lines as y = ax + b, with the x and y of the given point Draw a single point above your line, some distance away (like 3 inches) and give it a label. We will call ours P o i n t U. Step 2. Next, we will use our straightedge to construct a transverse, a line intersecting your original line and going through your point above the line. Try to make it at an angle not 90° Then we draw a line PF between the points P and F. This line is perpendicular to the given line. The equation of line PQ passinf through point (p x, p y) is: Find the intersection point of the line 2 x − y = 0 and the line passing through the point (5 , 2) and is perpendicular to the given line Draw a line segment PQ = 8 cm. Find point R on it such that PR = 4 3 PQ. Let XP and YQ intersect A. Step 4: Draw right bisector of XA intersecting XY at B. Step 5: Draw right bisector of YA intersecting XY at C. Through C , draw a line parallel to CA to meet AB at A . Then A BC is the required triangle

Ex 4.1, 5 - Draw rough figure and label (a) Point P lies ..

  1. Step3: Draw a line from point R to the point where the arcs intersect. This line is perpendicular to PQ and passes through the point R. How to construct a perpendicular to a line segment, through a point on the line? 1. Place compass point on the given point, and draw arc either side of point such that it intersects line twice. 2
  2. Given a spherical line 'obtained by intersection Swith a plane L, let mbe the straight line through Operpendicular to L. mwill intersection Sin two points called the poles of 'For example, the poles of the equator z= 0 are the north and south poles (0;0; 1). We have Theorem 106. Suppose that 'is a spherical line and P is a point not on '.
  3. What you have done is 1) look for a pattern. 2) made a conjecture. 3) used logical reasoning to verify your conjecture. That is what we do in geometry using definitions, postulates, properties and theorems to verify our conjectures

Draw a line segment of 10 cm

  1. @firelynx I think you are confusing the term line with line segment.The OP asks for a line intersection (on purpose or due to not understanding the difference). When checking lines for intersections on has to take into account the fact that lines are infinite that is the rays that start from its midpoint (defined by the given coordinates of the two points that define it) in both directions
  2. Click hereto get an answer to your question ️ Draw a line segment PQ = 8 cm. Construct the perpendicular bisector of the line segment PQ. Let the perpendicular bisector drawn meets PQ at point R. Measure the length of PR and QR. Is PR = QR
  3. The intersecting lines (two or more) meet only at one point always. The intersecting lines can cross each other at any angle. This angle formed is always greater than 0o and less than 180o . Two intersecting lines form a pair of vertical angles. The vertical angles are opposite angles with a common vertex (which is the point of intersection)
  4. Draw two rays whose intersection is a hne segment. 4 < Draw two rays whose intersection is a ray. S. What is the difference, if any, between . PQ,PQ,PQ, and . PQ? Explain. 6. Use the number line and Ruler Postulate to find Be (the length/distance from Bto C). •-1. B C

Draw a line PQ and mark a point O on it. Step 2. Place the pointer of the compasses at O and draw an arc of convenient radius which cuts the line PQ at a point say A. Step 3. With the pointer at A (as center), now draw an arc that passes through O. Step 4. Let the two arcs intersect at B. Join OB. We get ∠BOA whose measure is 60° Draw any line l. Take any point M on it and draw a line p perpendicular to l. With M as centre, cut off MC = 6 cm; At C, with initial line CM construct angles of measures 30° on both sides and let these lines intersect line l in A and B. Thus, ΔABC is the required triangle. 13. Draw a line segment QR = 5 cm. Construct perpendiculars at point. 1. In the following figure, lines AB and CD intersect at O. If ∠AOC + ∠BOE = 70° and ∠BOD = 40°, find ∠BOE and reflex ∠COE. Ans. Since AB is a straight line, ∴ AB and CD intersect at O. Thus, ∠BOE = 30° and reflex ∠COE = 250. 2. In the following figure, lines XY and MN intersect at O A line segment PQ is generally denoted by the symbol PQ, a line AB is denoted by the symbol AB and the ray OP is denoted by OP uuur. Give some examples of line segments and Draw two lines l and m, intersecting at a point. You can now mark ∠1, ∠2, ∠3 and ∠4 as in the Fig (5.16) (1) Draw a line segment XY. (2) Take a point M on XY and draw a line MP ⊥ XY. (3) With M as the centre and radius 4.3 cm, draw an arc cutting MP at A (4) Construct points B and C on XY such that ∠MAB = and ∠MAC = . Then, ABC is the required triangle Figure 1 illustrates point C, point M, and point Q. Figure 1 . Three points. Line. A line (straight line) can be thought of as a connected set of infinitely many points. It extends infinitely far in two opposite directions. A line has infinite length, zero width, and zero height. Any two points on the line name it